10x^2+13=3x^2+41

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Solution for 10x^2+13=3x^2+41 equation:


Simplifying
10x2 + 13 = 3x2 + 41

Reorder the terms:
13 + 10x2 = 3x2 + 41

Reorder the terms:
13 + 10x2 = 41 + 3x2

Solving
13 + 10x2 = 41 + 3x2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3x2' to each side of the equation.
13 + 10x2 + -3x2 = 41 + 3x2 + -3x2

Combine like terms: 10x2 + -3x2 = 7x2
13 + 7x2 = 41 + 3x2 + -3x2

Combine like terms: 3x2 + -3x2 = 0
13 + 7x2 = 41 + 0
13 + 7x2 = 41

Add '-13' to each side of the equation.
13 + -13 + 7x2 = 41 + -13

Combine like terms: 13 + -13 = 0
0 + 7x2 = 41 + -13
7x2 = 41 + -13

Combine like terms: 41 + -13 = 28
7x2 = 28

Divide each side by '7'.
x2 = 4

Simplifying
x2 = 4

Take the square root of each side:
x = {-2, 2}

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